x^2+(1.8*10^-5)x-(1.8*10^-8)=0

Solution for x^2+(1.8*10^-5)x-(1.8*10^-8)=0 equation:

x^2+(1.8*10^-5)x-(1.8*10^-8)=0

We add all the numbers together, and all the variables

x^2+(1.8*10^-5)x-8-1.8E=0

We multiply parentheses

x^2+18x^2-5x-8-1.8E=0

We add all the numbers together, and all the variables

19x^2-5x-12.8929072912=0

a = 19; b = -5; c = -12.8929072912;
Δ = b2-4ac
Δ = -52-4·19·(-12.8929072912)
Δ = 1004.86095413
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{1004.86095413}}{2*19}=\frac{5-\sqrt{1004.86095413}}{38}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{1004.86095413}}{2*19}=\frac{5+\sqrt{1004.86095413}}{38}
$